(0) Obligation:

The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(1, n^1).


The TRS R consists of the following rules:

active(f(X, X)) → mark(f(a, b))
active(b) → mark(a)
active(f(X1, X2)) → f(active(X1), X2)
f(mark(X1), X2) → mark(f(X1, X2))
proper(f(X1, X2)) → f(proper(X1), proper(X2))
proper(a) → ok(a)
proper(b) → ok(b)
f(ok(X1), ok(X2)) → ok(f(X1, X2))
top(mark(X)) → top(proper(X))
top(ok(X)) → top(active(X))

Rewrite Strategy: INNERMOST

(1) NestedDefinedSymbolProof (BOTH BOUNDS(ID, ID) transformation)

The following defined symbols can occur below the 0th argument of top: proper, active
The following defined symbols can occur below the 0th argument of proper: proper, active
The following defined symbols can occur below the 0th argument of active: proper, active

Hence, the left-hand sides of the following rules are not basic-reachable and can be removed:
active(f(X, X)) → mark(f(a, b))
active(f(X1, X2)) → f(active(X1), X2)
proper(f(X1, X2)) → f(proper(X1), proper(X2))

(2) Obligation:

The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(1, n^1).


The TRS R consists of the following rules:

f(mark(X1), X2) → mark(f(X1, X2))
top(ok(X)) → top(active(X))
proper(b) → ok(b)
f(ok(X1), ok(X2)) → ok(f(X1, X2))
active(b) → mark(a)
top(mark(X)) → top(proper(X))
proper(a) → ok(a)

Rewrite Strategy: INNERMOST

(3) CpxTrsMatchBoundsTAProof (EQUIVALENT transformation)

A linear upper bound on the runtime complexity of the TRS R could be shown with a Match-Bound[TAB_LEFTLINEAR,TAB_NONLEFTLINEAR] (for contructor-based start-terms) of 4.

The compatible tree automaton used to show the Match-Boundedness (for constructor-based start-terms) is represented by:
final states : [1, 2, 3, 4]
transitions:
mark0(0) → 0
ok0(0) → 0
b0() → 0
a0() → 0
f0(0, 0) → 1
top0(0) → 2
proper0(0) → 3
active0(0) → 4
f1(0, 0) → 5
mark1(5) → 1
active1(0) → 6
top1(6) → 2
b1() → 7
ok1(7) → 3
f1(0, 0) → 8
ok1(8) → 1
a1() → 9
mark1(9) → 4
proper1(0) → 10
top1(10) → 2
a1() → 11
ok1(11) → 3
mark1(5) → 5
mark1(5) → 8
ok1(7) → 10
ok1(8) → 5
ok1(8) → 8
mark1(9) → 6
ok1(11) → 10
active2(7) → 12
top2(12) → 2
active2(11) → 12
proper2(9) → 13
top2(13) → 2
a2() → 14
mark2(14) → 12
a2() → 15
ok2(15) → 13
active3(15) → 16
top3(16) → 2
proper3(14) → 17
top3(17) → 2
a3() → 18
ok3(18) → 17
active4(18) → 19
top4(19) → 2

(4) BOUNDS(1, n^1)

(5) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted Cpx (relative) TRS to CDT

(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(mark(z0), z1) → mark(f(z0, z1))
f(ok(z0), ok(z1)) → ok(f(z0, z1))
top(ok(z0)) → top(active(z0))
top(mark(z0)) → top(proper(z0))
proper(b) → ok(b)
proper(a) → ok(a)
active(b) → mark(a)
Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)), ACTIVE(z0))
TOP(mark(z0)) → c3(TOP(proper(z0)), PROPER(z0))
PROPER(b) → c4
PROPER(a) → c5
ACTIVE(b) → c6
S tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)), ACTIVE(z0))
TOP(mark(z0)) → c3(TOP(proper(z0)), PROPER(z0))
PROPER(b) → c4
PROPER(a) → c5
ACTIVE(b) → c6
K tuples:none
Defined Rule Symbols:

f, top, proper, active

Defined Pair Symbols:

F, TOP, PROPER, ACTIVE

Compound Symbols:

c, c1, c2, c3, c4, c5, c6

(7) CdtLeafRemovalProof (BOTH BOUNDS(ID, ID) transformation)

Removed 3 trailing nodes:

PROPER(b) → c4
ACTIVE(b) → c6
PROPER(a) → c5

(8) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(mark(z0), z1) → mark(f(z0, z1))
f(ok(z0), ok(z1)) → ok(f(z0, z1))
top(ok(z0)) → top(active(z0))
top(mark(z0)) → top(proper(z0))
proper(b) → ok(b)
proper(a) → ok(a)
active(b) → mark(a)
Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)), ACTIVE(z0))
TOP(mark(z0)) → c3(TOP(proper(z0)), PROPER(z0))
S tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)), ACTIVE(z0))
TOP(mark(z0)) → c3(TOP(proper(z0)), PROPER(z0))
K tuples:none
Defined Rule Symbols:

f, top, proper, active

Defined Pair Symbols:

F, TOP

Compound Symbols:

c, c1, c2, c3

(9) CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID) transformation)

Removed 2 trailing tuple parts

(10) Obligation:

Complexity Dependency Tuples Problem
Rules:

f(mark(z0), z1) → mark(f(z0, z1))
f(ok(z0), ok(z1)) → ok(f(z0, z1))
top(ok(z0)) → top(active(z0))
top(mark(z0)) → top(proper(z0))
proper(b) → ok(b)
proper(a) → ok(a)
active(b) → mark(a)
Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
S tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
K tuples:none
Defined Rule Symbols:

f, top, proper, active

Defined Pair Symbols:

F, TOP

Compound Symbols:

c, c1, c2, c3

(11) CdtUsableRulesProof (EQUIVALENT transformation)

The following rules are not usable and were removed:

f(mark(z0), z1) → mark(f(z0, z1))
f(ok(z0), ok(z1)) → ok(f(z0, z1))
top(ok(z0)) → top(active(z0))
top(mark(z0)) → top(proper(z0))

(12) Obligation:

Complexity Dependency Tuples Problem
Rules:

active(b) → mark(a)
proper(b) → ok(b)
proper(a) → ok(a)
Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
S tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
K tuples:none
Defined Rule Symbols:

active, proper

Defined Pair Symbols:

F, TOP

Compound Symbols:

c, c1, c2, c3

(13) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
We considered the (Usable) Rules:none
And the Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(F(x1, x2)) = x1   
POL(TOP(x1)) = 0   
POL(a) = 0   
POL(active(x1)) = 0   
POL(b) = 0   
POL(c(x1)) = x1   
POL(c1(x1)) = x1   
POL(c2(x1)) = x1   
POL(c3(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(ok(x1)) = [1] + x1   
POL(proper(x1)) = 0   

(14) Obligation:

Complexity Dependency Tuples Problem
Rules:

active(b) → mark(a)
proper(b) → ok(b)
proper(a) → ok(a)
Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
S tuples:

TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
K tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
Defined Rule Symbols:

active, proper

Defined Pair Symbols:

F, TOP

Compound Symbols:

c, c1, c2, c3

(15) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

TOP(mark(z0)) → c3(TOP(proper(z0)))
We considered the (Usable) Rules:

proper(b) → ok(b)
active(b) → mark(a)
proper(a) → ok(a)
And the Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(F(x1, x2)) = x2   
POL(TOP(x1)) = x1   
POL(a) = 0   
POL(active(x1)) = x1   
POL(b) = [1]   
POL(c(x1)) = x1   
POL(c1(x1)) = x1   
POL(c2(x1)) = x1   
POL(c3(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(ok(x1)) = x1   
POL(proper(x1)) = x1   

(16) Obligation:

Complexity Dependency Tuples Problem
Rules:

active(b) → mark(a)
proper(b) → ok(b)
proper(a) → ok(a)
Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
S tuples:

TOP(ok(z0)) → c2(TOP(active(z0)))
K tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(mark(z0)) → c3(TOP(proper(z0)))
Defined Rule Symbols:

active, proper

Defined Pair Symbols:

F, TOP

Compound Symbols:

c, c1, c2, c3

(17) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

TOP(ok(z0)) → c2(TOP(active(z0)))
We considered the (Usable) Rules:

proper(b) → ok(b)
active(b) → mark(a)
proper(a) → ok(a)
And the Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(F(x1, x2)) = x1 + x2   
POL(TOP(x1)) = x1   
POL(a) = 0   
POL(active(x1)) = x1   
POL(b) = [1]   
POL(c(x1)) = x1   
POL(c1(x1)) = x1   
POL(c2(x1)) = x1   
POL(c3(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(ok(x1)) = [1] + x1   
POL(proper(x1)) = [1] + x1   

(18) Obligation:

Complexity Dependency Tuples Problem
Rules:

active(b) → mark(a)
proper(b) → ok(b)
proper(a) → ok(a)
Tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(ok(z0)) → c2(TOP(active(z0)))
TOP(mark(z0)) → c3(TOP(proper(z0)))
S tuples:none
K tuples:

F(mark(z0), z1) → c(F(z0, z1))
F(ok(z0), ok(z1)) → c1(F(z0, z1))
TOP(mark(z0)) → c3(TOP(proper(z0)))
TOP(ok(z0)) → c2(TOP(active(z0)))
Defined Rule Symbols:

active, proper

Defined Pair Symbols:

F, TOP

Compound Symbols:

c, c1, c2, c3

(19) SIsEmptyProof (BOTH BOUNDS(ID, ID) transformation)

The set S is empty

(20) BOUNDS(1, 1)